WebSep 29, 2024 · libnum. This is a python library for some numbers functions: working with primes (generating, primality tests) common maths (gcd, lcm, n'th root) modular arithmetics (inverse, Jacobi symbol, square root, solve CRT) converting strings to numbers or binary strings. Library may be used for learning/experimenting/research purposes. Web会员账号使用规范 Powered by CTFd 陕ICP备20010271号-2 陕公网安备 61040202400507号 版权:ctf.show 论坛:bbs.ctf.show 友链:CTFhub 攻防世界 青少年CTF
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秘钥生成过程 1.选择两个不相等的质数p和q 2.计算q与p的乘积n 3.计算n的欧拉函数φ(n) 4.选择一个整数e,条件是1< e < φ(n),且e与φ(n) 互质 5.计算e对于φ(n)的模反元素d(如果两个正整数a和n互质,那么一定可以找到整数b,使得 ab-1 被n整除,或者说ab被n除的余数是1。这时,b就叫做a的“模反元素”。) 用公式表 … See more 其中m为模数,r为余数 讨论推导过程,如下: 1.余数计算: 总可以找到一个a∈Z,使得 由于a - r = q · m(m除a-r),上面的表达式可 … See more 可以通过一种简单方法判断给定元素a的逆元是否存在: 当且仅当gcd(a,m) = 1,一个元素a∈Z存在乘法逆元a⁻¹,其中gcd表示最大公约数。 举例: Z₂₆中15的乘法逆元是否存在? Z₂₆中14的乘法逆元是否存在? See more easyrsa1 利用factordb在线分解n,得到 写脚本 easyrsa2 题目中e相同,n,c不同,求出n1与n2的最大公因数即为p,之后就可以得到q和d,从而 … See more WebThe original Baudot code was invented by Émelie Baudot in 1870. It was a 5-bit code that became known as the International Telegraph Alphabet No 1 (ITA1). In 1901, the code was improved by Donald Murray. Murray designed the code to minimize the wear on the machinery. He assigned the most frequently used symbols and letters to the codes with ... sushi in hamilton
hellman/libnum: Working with numbers (primes, modular, etc.) - Github
WebNew Awesome Version 1.0 is now Done! Jarvis OJ is a CTF training platform developed by Jarvis from USSLab in ZJU. This platform will collect or make a series of problems having a good quality for CTFers to solve. Hope you can improve your … WebMar 16, 2024 · 很简单的一个rsa,就是再求取欧拉函数是对于(p-1)(q-1)的获取要先进行一步转换,题中给出了p和q的关系式,及一个求导的过程,化简后可以得出z=p^2+q^2,最后再根据n=pq,即可得出(p-1)*(q … http://serpent.online-domain-tools.com/ sushi inhaltsstoffe